As a train enters the station it slows down from 40 m/s to a 10 m/s in 5 seconds 1 what is the acceleration of the train

2 how far does the train travel during this time

See the answers below.

Explanation:

To solve this problem we must use the following equation of kinematics.

where:

Vf = final velocity = 10 [m/s]

Vo = initial velocity = 40 [m/s]

t = time = 5 [s]

a = acceleration [m/s²]

Now replacing:

Note: The negative sign in the above equation means that the velecity is decreasing.

2)

To solve this second part we must use the following equation of kinematics.

where:

x = distance [m]

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

it's a b and