![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{1}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{(7-1)^2+(-1-7)^2}\implies d=\sqrt{6^2+(-8)^2} \\\\\\ d=\sqrt{36+64}\implies d=\sqrt{100}\implies d=10~\hfill \stackrel{\textit{half of that or radius}}{r = 5} \\\\[-0.35em] ~\dotfill](/tpl/images/0159/9550/ccc5f.png)
![\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{1}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{-1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{7+1}{2}~~,~~\cfrac{-1+7}{2} \right)\implies \left( \cfrac{8}{2}~,~\cfrac{6}{2} \right)\qquad \implies \qquad \stackrel{center}{(4,3)} \\\\[-0.35em] ~\dotfill](/tpl/images/0159/9550/20718.png)
![\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{4}{ h},\stackrel{3}{ k})\qquad \qquad radius=\stackrel{5}{ r} \\\\\\ (x-4)^2+(y-3)^2=5^2\implies (x-4)^2+(y-3)^2=25 \\\\\\ \stackrel{\mathbb{F~O~I~L}}{(x^2-8x+16)}+\stackrel{\mathbb{F~O~I~L}}{(y^2-6y+9)}=25\implies x^2-8x+y^2-6y+25=25 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill x^2+y^2-8x-6y=0~\hfill](/tpl/images/0159/9550/ab83b.png)
(1,7)
(8,6)
Mathematics, 02.08.2019 01:10 erinrae
Write the general equation for the circle that passes through the points:
(1,7)
(8,6)
(7,-1)
you must include the appropriate sign (+or-) in your answer. do not use spaces in your answer.
x^2+y^2__x__y=0
Answers: 1
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Write the general equation for the circle that passes through the points:
(1,7)
(8,6)
(1,7)
(8,6)
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