Ineed to answer this before 11: 59pm est, today , i would appreciate your .
an object is thrown upward at a speed of 58 feet per second by a machine from a height of 7 feet off the ground. the height h of the object after t seconds can be found using the equation h=−16t^2+58t+7
when will the height be 17 feet?
when will the object reach the ground?

0.18 sec or 3.4 sec.

For second part, it will take 3.7 sec.

First part:

Set h(t) = 17and solve for t.

-16t²+ 58t + 7= 17

-16t² + 58t - 10 = 0

Solve this quadratic equation for t. You should get 2 positive solutions. The lower value is the time to reach 17 on the way up, and the higher value is the time to reach 17 again, on the way down.

Second part:

Set h(t) = 0 and solve the resulting quadratic equation for t. You should get a negative solution (which you can discard), and a positive solution. The latter is your answer.

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step-by-step explanation:

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.