WILL MARK BRAINLIEST

A pyramid has a base 16 inches x 16 inches and a slant height of 10 inches.

You will need to use the Pythagorean theorem to find the altitude.

Volume = cubic in.
Surface area = sq. in.

This is the example it gives in the lesson below I have tried and tried but I cant get it right!

Volume of a pyramid: V = 1/3(area of base) x (altitude).

A pyramid has a base 24 inches x 24 inches and a slant height of 20 inches. What is its surface area?

SA = 1/2(perimeter of base) x (slant height) + (area of base).
SA = 1/2(96) x 20 + 576
SA = 48 x 20 + 576
SA = 960 + 576
SA = 1,536 in2

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

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step-by-step explanation:

my guess is

step-by-step explanation:

the area of a triangle is determined by the formula: base x height * 1/2

you'll need to assign a base to the triangle. based on the vertices given, the simplest base would be the line segment from (-2,1) to (2,1). the distance between any two numbers is found by just subtracting them. here, you should subtract the x values to find the distance of this side.

2 - (-2) = 4.

so the distance (aka the length of the base) is 4. the height of the triangle is the distance between the base and the highest point on the triangle which is (3,4). we should subtract the y values this time to find the height/distance.

4 - 1 = 3

so the height is 3.

base = 4

height = 3

hope this if needed hmu