Vector g is 40.3 m long in a -35.0 degree direction. vector h is 63.3 m long in a 270 direction. find the magnitude and direction of their vector sum.

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west

answer: the value of b is 24 + 3t / (4- t ) = b

solution:

step 1 : find the slope using the formula below with the c (t, 3) and d(4, -3)

m = y2-y1 / x2 - x1

m = -3 -3 / 4-t

m = -6/4-t

to find the value of   b use the equation given in the question

note : use any of the pair given c or d in the equation to find the value of b i will be using d ( 4, -3)

y = mx+ b

3 = (-6/4-t)(4) + b don't forget to take the lcm

b = (36 - 3 t ) / ( 4 - t )