Consider a sampling distribution with p equals 0.09 and samples of size n each. using the appropriate formulas, find the mean and the standard error of the sampling distribution of the sample proportion. a. for a random sample of size n equals 4000. b. for a random sample of size n equals 1000. c. for a random sample of size n equals 500.

step-by-step explanation:

20% of 120 is 24. if you subtract 24 from 120 you get 96

0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation:

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.