Rosa bought 1 pound of cashews and 2 pounds of peanuts for $10. at the same store, sabrina bought 2 pounds of cashews and 1 pound of peanuts for $11. find the cost per pound of cashews and peanuts.

The solutions are x=4, y=3. Cashews are $4 per pound and Peanuts are $3 per pound.

Step-by-step explanation:

let x = cashews

let y = peanuts

x + 2y = 10 - rosa's purchase

2x + y = 11 - sabrina's purchase

subtract 2x to isolate 'y'

y = 11 - 2x

x + 2(11 - 2x) = 10

x + 22 - 4x = 10 (Use the distributive property.)

-3x = -12

x = 4.00

Plug this into the original equations to find "y"

2(4) + y = 11

8 + y = 11

y = 3

4 + 2y = 10

2y = 6

y = 3

the solutions are: x = 4. y = 3.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

3.how is solving radical equations different than solving linear equations?

step-by-step explanation: