6. a square is inscribed in a circle. the sic
length of the square is 4 centimeters,
calculate the area of the shaded region.

9.13 cm^2.

Step-by-step explanation:

The diagonal of the square = the diameter of the circle.

The length of the diagonal = 4√2 cm (because we have a 45-45-90 triangle), so the radius of the circle is half of this = 2√2 cm.

The area of the shaded part = area of the circle - area of the square

= π (2√2)^2 - 4^2

=  25.13 - 16

= 9.13 cm^2.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this