Mathematics, 28.06.2019 21:40 finldani4

Mrs. culland is finding the center of a circle whose equation
is x2 + y2 + 6x + 4y - 3 = 0 by completing the square. her
work is shown.
x2 + y2 + 6x + 4y – 3 = 0
x2 + 6x + y2 + 4y - 3 = 0
(x2 + 6x) + (y2 + 4y) = 3
(x2 + 6x + 9) + (x2 + 4y + 4) = 3 + 9 + 4

Answers: 3

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Mrs. culland is finding the center of a circle whose equation
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More questions: Mathematics Another questions

Mrs. culland is finding the center of a circle whose equation is x2 + y2 + 6x + 4y - 3 = 0 by completing the square. her work is shown. x2 + y2 + 6x + 4y – 3 = 0 x2 + 6x + y2 + 4y - 3 = 0 (x2 + 6x) + (y2 + 4y) = 3 (x2 + 6x + 9) + (x2 + 4y + 4) = 3 + 9 + 4

Answers

Another question on Mathematics

Mrs. culland is finding the center of a circle whose equation
is x2 + y2 + 6x + 4y - 3 = 0 by completing the square. her
work is shown.
x2 + y2 + 6x + 4y – 3 = 0
x2 + 6x + y2 + 4y - 3 = 0
(x2 + 6x) + (y2 + 4y) = 3
(x2 + 6x + 9) + (x2 + 4y + 4) = 3 + 9 + 4