If 30 coins in quarters and dimes are worth $4.80, how many of each coin are there?

There are 18 dimes and 12 quarters

Step-by-step explanation:

Remember that

1 Dime =$0.10

1  Quarter=$0.25

Let

x> the number of dimes

y> the number of quarters

we know that

x+y=30

x=30-y > equation A

0.10x+0.25y=4.80

Multiply by 100 both sides

10x+25y=480 > equation B

Substitute equation A in equation B and solve for y

10(30-y)+25y=480

300-10y+25y=480

15y=180

y=12 quarters

Find the value of x

x=30-y=30-12=18 dimes

therefore

There are 18 dimes and 12 quarters

312312

step-by-step explanation:

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length