Suppose a lake contains blue and green algae. the blue algae has an initial mass of 20 kg and doubles its mass every hour. the green algae has an initial mass of 160 kg and grows at a constant rate of 0.20 kg per minute.

which algae has a larger mass at 3 hours, in kilograms?
a) the blue algae has 12 kg more mass at 3 hours.
b) the green algae has 12 kg more mass at 3 hours.
c) the blue algae has 36 kg more mass at 3 hours.
d) the green algae has 36 kg more mass at 3 hours.

which algae has a larger mass at 4 hours, in kilograms?
a) the blue algae has 56 kg more mass at 4 hours.
b) the green algae has 56 kg more mass at 4 hours.
c) the blue algae has 112 kg more mass at 4 hours.
d) the green algae has 112 kg more mass at 4 hours

1) D

2) C

Step-by-step explanation:

1. The blue algae has an initial mass of 20 kg and doubles its mass every hour. Then after t hours, the mass of blue algae is

2. The green algae has an initial mass of 160 kg and grows at a constant rate of 0.20 kg per minute. Then after t hours (60t minutes), the mass of green algae is

Part I) At t=3:

The mass of green algae has 196-160=36 kg more mass at 3 hours.

Part II) At t=4:

The blue algae has 320-208=112 kg more mass at 4 hours.

b. 24 mm

step-by-step explanation:

use the pythagorean theorem.

a^2 + b^2 = c^2

a^2 + 7^2 = 25^2

a^2 + 49 = 625

a^2 = 576

a = 24

answer: b. 24 mm

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: