In 2000 the population of a district was 750,000. with a continuously compounding growth rate of approximately 4%, what will the population be in 2025?

2,038,711

Step-by-step explanation:

For a continuously compounding rate r, the growth is modeled by ...

P = P0·e^(rt)

where P0 is the initial population, r is the annual growth rate (compounded continuously) and t is the number of years.

Putting your values into this formula, you have

P = 750000·e^(0.04·25) ≈ 2,038,711

f(x) is going down by 4

step-by-step explanation:

(its either that or its going left by 4)

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.