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a customer went to a garden shop and bought some potting soil for $17.50 and 4 shrubs. the total bill was $53.50. write and solve an equation to find the price of each shrub.

4p + $17.50 = $53.50; p = $11.25

4(p + $17.50) = $53.50; p = $4.00

4p + $17.50 = $53.50; p = $9.00

4p + 17.5 p = $53.50; p = $2.49

You would need to multiply the quantity of shrubs bought by the price of each one, so 4p and add that to the price of the soil to get the total cost

The equation becomes 4p + 17.50 = 53.50

Now solve for p:

4p +17.50 = 53.50

Subtract 17.50 from both sides:

4p = 36

Divide both sides by 4:

p = 36/4

p = 9

The answer would be: 4p + $17.50 = $53.50; p = $9.00

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: