What would x/2x-14 • x^2-7x/5 equal to

x2+7x-2x-14  

Final result :

 (x + 7) • (x - 2)

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2"   was replaced by   "x^2".  

Step by step solution :

Step  1  :

Trying to factor by splitting the middle term

1.1     Factoring  x2+5x-14  

The first term is,  x2  its coefficient is  1 .

The middle term is,  +5x  its coefficient is  5 .

The last term, "the constant", is  -14  

Step-1 : Multiply the coefficient of the first term by the constant   1 • -14 = -14  

Step-2 : Find two factors of  -14  whose sum equals the coefficient of the middle term, which is   5 .

     -14    +    1    =    -13  

     -7    +    2    =    -5  

     -2    +    7    =    5    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -2  and  7  

                    x2 - 2x + 7x - 14

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x • (x-2)

             Add up the last 2 terms, pulling out common factors :

                   7 • (x-2)

Step-5 : Add up the four terms of step 4 :

                   (x+7)  •  (x-2)

            Which is the desired factorization

Final result :

 (x + 7) • (x - 2)

heyyy

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3