Arectangular room is 4 meters longer than it is wide, and its perimeter is 32 meters. find the dimension of the room.

The dimensions of the room are 6 m and 10 m

Step-by-step explanation:

Let the width of the room is x

∴ Its length = x + 4

∵ The perimeter of the rectangle = 2(length + width)

∴ 2(x + 4 + x) = 32

∴ 2(2x + 4) = 32

∴ 4x + 8 = 32

∴ 4x = 24

∴ x = 24/4 = 6

∴ The length = 6 + 4 = 10 m

∴ The width = 6 m

the distance from any point on the parabola to the focus is the exact same as the distance from that point to the directrix.

if you could provide answer choices that might allow me to answer the question easier if my above answer isn't an option! (:

the answer is 28

step-by-step explanation: