Given that the quadrilateral is a kite, prove that.

Using SSS Congruence Property, we get ΔIKE ≅ ΔITE

Step-by-step explanation:

We are given a quadrilateral which is a 'kite'.

Now, according to the properties of Kite, we have that,

The two disjoint pairs of consecutive sides are congruent.

Thus, from the figure,

KI ≅ TI and KE ≅ TE

Also, side IE is the common side for both the triangles.

So, for ΔIKE ≅ ΔITE,

KI ≅ TI and KE ≅ TE and IE ≅ IE

Thus, using SSS Congruence Property, we get ΔIKE ≅ ΔITE

han when lo ahe whn hew anh ? ?

explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)