Using triangle a b c as the pre-image and the origin as the center of dilation, which coordinate point is not a coordinate of a dilation that uses a scale factor of 4?

coordinate plane ranging from negative five to five on the x and y axes. point a is at (negative one, three), point b is at (two, one) and point c is at (negative two, one). the three points are connected to form a triangle.

question 4 options:

begin ordered pair 4 comma 12 end ordered pair

begin ordered pair negative 4 comma 12 end ordered pair

begin ordered pair 8 comma 4 end ordered pair

begin ordered pair negative 8 comma negative 4 end ordered pair

The correct option is:

begin ordered pair 4 comma 12 end ordered pair i.e. (4,12).

Step-by-step explanation:

We are given the coordinates of the point A,B and C of the triangle ΔABC as:

A(-1,3) , B(2,1) and C(-2,-1).

Now it is given that there is dilation of this triangle about the origin with a scale factor of 4.

This means that the change in the coordinates after the transformation is given by the rule:

(x,y) → (4x,4y)

As A → A' , B → B' and C → C'

Hence the coordinates A',B' and C' are given by:

A' are (4×-1,4×3)=(-4,12)

B' are (4×2,4×1)=(8,4)

and C' are (4×-2,4×-1)=(-8,-4).

Hence the coordinate point which is not a coordinate of dilation is:

begin ordered pair 4 comma 12 end ordered pair  i.e. (4,12)

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.