In a small town, there are 4 times as many left-handed males as there are left-handed females, and there are 3 times as many right-handed females as there are right-handed males. there are a total of 204 males and 348 females in the town.
let x represent the number of left-handed females, and let y represent the number of right-handed males. write a system of equations to represent the situation. what is the value of x, the number of left-handed females?

Hey there, This is how you would figure it out. 

left handed females = x
right handed females = 348 - x
right handed males = y
left handed males = 204 - y

204 - y = 4x
348 - x = 3y

4x + y = 204  . . . . . . . (1)
x + 3y = 348  . . . . . . . (2)

From (2),  x = 348 - 3y
subsituting for x in (1), we have
4(348 - 3y) + y = 204
1392 - 12y + y = 204
12y - y = 1392 - 204
11y = 1188
y = 1188/11 = 108

x = 348 - 3y = 348 - 3(108) = 348 - 324 = 24

So, the value of x is 24!

Hope I helped! Have a Good Day!

The answer is 109 times per second