What is the four-digit number in which the first digit is one-third the second, the third is the sum of the first and second, and the last is three times the second?

1,349

Step-by-step explanation:

Using the verbal descriptions from the problem, we can set up the following expressions for each number:

first: 'one-third the second' =

second: 'x'

third: 'the sum of the first and second' = + x =

fourth: 'three times the second' = 3x

Since the four-digit number has to be whole numbers, the first choice would be the integer '3':

first:

second: x = 3

third:

fourth: 3x = 3(3) = 9

final  1,349

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

assuming you mean addition: addition and subtraction are reverse operations.

step-by-step explanation: