Factor the polynomial: -2x^3 - 4x^2 - 6x a. 2x(x^2 + 2x + 3) b. -2x(x^2 + 2x +3) c. -2x(-x^2 - 4x - 6) d. -2x(-x^2 - 2x - 3)

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-2x3-4x2-6x

Final result :

 -2x • (x2 + 2x + 3)

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 ((0 -  (2 • (x3))) -  22x2) -  6x

Step  2  :

Equation at the end of step  2  :

 ((0 -  2x3) -  22x2) -  6x

Step  3  :

Step  4  :

Pulling out like terms :

4.1     Pull out like factors :

  -2x3 - 4x2 - 6x  =   -2x • (x2 + 2x + 3)

Trying to factor by splitting the middle term

4.2     Factoring  x2 + 2x + 3

The first term is,  x2  its coefficient is  1 .

The middle term is,  +2x  its coefficient is  2 .

The last term, "the constant", is  +3

Step-1 : Multiply the coefficient of the first term by the constant   1 • 3 = 3

Step-2 : Find two factors of  3  whose sum equals the coefficient of the middle term, which is   2 .

     -3    +    -1    =    -4

     -1    +    -3    =    -4

     1    +    3    =    4

     3    +    1    =    4

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Final result :

 -2x • (x2 + 2x + 3)

Step-by-step explanation:

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step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?