"at $1.29 million, they closed last month percent above what they paid in 2007." how much did they pay in 2007?

 Amount that they paid in 2007 is 1.01 millions.

Step-by-step explanation:

Since we have given that

Number of millions paid last month = $1.29 millions

According to question, it was 26% above what they paid in 2007.

Let the amount paid in 2007 be x

So, our equation becomes,

Hence, Amount that they paid in 2007 is 1.01 millions.

The amount they paid in 2007 is:

                         $ 1.02381 million

Let the amount paid by them in 2007 be: $ x

Now, it is given that:

"At $1.29 million, they closed last month for...26 percent above what they paid in 2007."

i.e.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

d is the only accurate one

step-by-step explanation: