Five numbers, x, 2x, 2x + 6, 3x – 1 and 4x – 8, are in a set. if the average (arithmetic mean) of the five numbers is 9, what is the value of the mode in this set?

mode = 8

Step-by-step explanation:

Find the value of x by using the average formula, that is

= 9

= 9 ( multiply both sides by 5 )

12x - 3 = 45 ( add 3 to both sides )

12x = 48 ( divide both sides by 12 )

x = 4

The set of 5 numbers is

4, 8, 14, 11, 8

The mode is the value in the set which occurs most

mode = 8

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

its adding 5.5 each time

step-by-step explanation: