The equation of circle a is x^2+y^2+cx+dy+e=0. if the circle is moved horizontally to the left of the y axis without changing the radius how are the coefficients c and d affected

When the circle A moves horizontally to left of y-axis, it changes the value of C in the equation.

Step-by-step explanation:

Given is the equation of a circle A as follows:-

x^2+y^2+Cx+Dy+E=0

We see the coefficients of x^2 and y^2 terms are 1 each. It means we can find the center of the circle from the equation itself as follows:-

Coordinates of center of circle A: (-C/2 , -D/2)

When they move the circle horizontally to the left of the y-axis, without changing its radius, the x-coordinate of the center (i.e. -c/2) in the circle A will change accordingly. And y-coordinate remains unchanged.

So when we move the circle horizontally to the left of y-axis, it changes the value of C in the equation of circle.

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )