What is the standard form equation of the line shown below? (1 point) graph of a line going through negative 3, negative 1 and 3, 2 y + 1 = one half(x + 3) y = one halfx + five halves −x + 2y = 1 x − 2y = −1

x-2y=-1

Step-by-step explanation:

To write the equation of a line we must have a slope and a point. To find the slope we use the slope formula and substitute (x,y) points in it as shown below:

Now that we have the slope, plug in the slope and choose one point to plug into the point slope formula. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.  

(y--1)=1/2(x--3)  

y+1=1/2(x+3)

y+1=1/2x+3/2

y=1/2x + 1/2

Now convert to standard form, Ax+By=C.

y=1/2x + 1/2

2y = x +1

-x+2y+1 (multiply by -1 since A cannot be negative)

x-2y=-1

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

$9.41

step-by-step explanation: