If -1 is a zero of polynomial ax^²-x²+x+4, find the value of a

a = -2

Step-by-step explanation:

Given that,

-1 is a zero of the polynomial. i.e. x = -1.

The polynomial is :

p(x) = ax²-x²+x+4

We need to find the value of a.

Put x = -1 in the above polynomial.

p(1) = a(-1)²-(-1)²+(-1)+4

For zeroes,

p(1) = 0

a(-1)²-(-1)²+(-1)+4 = 0

a-1-1+4 = 0

a = -2

So, the value of a is equal to -2.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

answer: on kudzu, being female and being green are independent events.

step-by-step explanation: