The concentration of the mixture obtained by mixing two solutions, a and b, is 6 2/3 %. the concentration of the second mixture obtained by mixing the same two solutions is 16.7%. find the concentration of each of the solutions a and b, if the first mixture is obtained by mixing them in 2: 7 ratio and the second is obtained by mixing them in 7: 3 ratio.

Concentration of solution A = 23%

and concentration of solution B = 2%

Step-by-step explanation:

Lets get started

lets say that we concentration of solution A be x% and concentration of second solution be y%

we also know that first mixture is obtained by mixing them in ratio of 2:7

so linear equation representing this situation can be written as:

2(x%)+7(y%)= 9(6.66%)    

changing percentage to decimal we get,

.02x+.07y=9(.0666)

.02x+.07y = 0.6          (equation 1 )

similarly , second mixture is obtained by mixing them in ratio of 7:3

so linear equation can be written as:

7(x%)+3(y%) = 10(16.7%)

.07x +.03y = 1.67     (equation 2)

solving equations 1 and 2  we get

x =  23 and y = 2

so concentration of solution A = 23%

and concentration of solution B = 2%

That's the final answer

Hope it was helpful !!

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%

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step-by-step explanation:

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