Mathematics, 29.06.2019 00:30 luhmama
Calculate the sum of the first 36 terms of the arithmetic sequence defined in which a36=14 and the common difference is d=1/8
Answers: 2
, it means that from the first term, we add 
![S_{n}=\frac{n}{2}[2a+(n-1)d]](/tpl/images/0029/0796/c9fce.png)
is the sum of nth term (we want to figure this out for first 36 terms)
is the first term (we figured this out to be 9.625)
is the term number (36 for our case)
is the common difference (given as ![S_{36}=\frac{36}{2}[2(9.625)+(36-1)(\frac{1}{8})]\\S_{36}=18[19.25+4.375]\\S_{36}=18[23.625]\\S_{36}=425.25](/tpl/images/0029/0796/dc543.png)
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Calculate the sum of the first 36 terms of the arithmetic sequence defined in which a36=14 and the c...
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