On the main street, the tourists walked for s km with a speed of v km/hour. on the side road, the tourists walked twice the distance that they covered on the main street. how much time t (in hours) did the tourists spend if it is known that on the side road they walked with a speed that was 2 km/hour less than their speed on the main road? find t when s=10, v=6.

6 2/3 hours

Step-by-step explanation:

We assume the time of interest is the total time spent on the main road and side road.

In each case, ...

... time = distance/speed

On the main road, ...

... tmain = s/v

On the side road, ...

... tside = (2s)/(v -2)

Then the total time spent is ...

... ttotal = tmain + tside

... = s/v + (2s)/(v -2)

For s=10 and v=6, this is ...

... ttotal = 10/6 + 2·10/(6 -2) = 5/3 + 20/4 = 5/3 + 5 . . . . hours

... ttotal = 6 2/3 hours

step-by-step explanation:

i hate black

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10