Slope intercept form of the line that passes through (2,1) and is parallel to 6x-3y=12

The slope intercept form of the equation would be y = 2x - 3

Step-by-step explanation:

Firstly, you need to find the slope of the original line. To do so, we need to solve the original line for y.

6x - 3y = 12

-3y = -6x + 12

y = 2x - 4

Now we know the original slope is 2 (since it is the coefficient of x). Now we use that slope and the point in point-slope form and solve it for y.

y - y1 = m(x - x1)

y - 1 = 2(x - 2)

y - 1 = 2x - 4

y = 2x - 3

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

0lz try yourself sorry for not answering