Solve: find two consecutive odd numbers such that the sum of the larger number and twice the smaller number is 27 less than four times the smaller number.

The answer is: 29 and 31.

1. Let's call the smaller odd number: .

2. Let's call the larger odd number:

3. Based on the information given in the problem, the sum of the larger number () and twice the smaller number () is 27 less than four times the smaller number ().

4. Then, you can write the following expression and solve for to find the smaller number:

5. Therefore, the larger number is:

Smaller number = 29 and larger number = 31.

Step-by-step explanation:

Let the two consecutive odd numbers be x (smaller number) and x+2 (larger number).

We know that the sum of the larger number (x+2) and twice the smaller number (2x) is equal to 27 less than four times the smaller number (= 4x - 27). So we can write it as:

Solving for to get:

and

Therefore the smaller number = 29 and larger number = 31.

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