Which of the following functions best describes this graph? a. y=x^2+9x+18 b. y=(x-3)(x-6) c. y=x^2-2x+4 d. y=(x+5)(x-4)

A.

Step-by-step explanation:

By the given graph,

The function is intersecting x-axis at - 3 and - 6,

Thus, the x-intercepts of the given function must be (-3,0) and (-6,0),

Now, In option  A,

The function is,

For x-intercept y = 0,

⇒ x-intercepts are (-3,0), (-6,0)

⇒ The function describes the given graph,

Now, In option  B,

The function is,

For x-intercept y = 0,

⇒ x-intercepts are (3,0), (6,0)

⇒ The function does not describe the given graph,

Now, In option  C,

The function is,

For x-intercept y = 0,

⇒ x-intercept is (2,0),

⇒ The function doesn't describe the given graph,

Now, In option D,

The function is,

For x-intercept y = 0,

⇒ x-intercepts are (-5,0), (4,0)

⇒ The function does not describe the given graph.

i understand 100% 10/10 hit or miss?

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.