1. answer the questions by drawing on the coordinate plane below. (2 points possible) (a) draw the image of ∆jkl after a rotation of 90°counterclockwise about the origin. label the image ∆j′k′ l′. (b) draw the image of ∆jkl after a reflection across the y-axis. label the image ∆j′′k′′l′′..

90 degrees counterclockwise

Invert the x and y points  and the y becomes negative (x, y) > (-y, x).

J( -4, 1) becomes (-1,-4)

K( -4,-2) becomes (2,-4)

L (-3,-1) becomes (1,-3)

reflection across the y axis

the x becomes negative (x, y) > (-x, y).

J( -4, 1) becomes (4,-1)

K( -4,-2) becomes (4,-2)

L (-3,-1) becomes (3,1)

(a) The vertices of image are J'(-1,-4), K'(2,-4) and L'(1,-3).

(b) The vertices of image are J''(4,1), K''(4,-2) and L''(3,-1).

Step-by-step explanation:

From the given figure it is clear that J(-4,1), K(-4,-2) and L(-3,-1).

(a)

If a figure rotated 90°counterclockwise about the origin, then

The vertices of image of ∆JKL after a rotation of 90°counterclockwise about the origin are

Therefore the vertices of image are J'(-1,-4), K'(2,-4) and L'(1,-3).

(b)

If a figure reflected across the y-axis, then

The vertices of image of ∆JKL after a reflection across the y-axis are

Therefore the vertices of image are J''(4,1), K''(4,-2) and L''(3,-1).

okay so 15.15 *()5: +5/6

step-by-step explanation:

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)