One number is seven less than five times another. if their sum is increased by one, the result is twelve. find the numbers

x = 8

y = 3

x = 5y - 7

x + y + 1 = 12

Because we have a value for x, we can use it in the second equation to find the value of y.

5y - 7 + y + 1 = 12

Combine like terms

6y - 6 = 12

Add 6 to both sides.

6y = 18

Divide both sides by 6.

y = 3

Now that we have a value for y we can place it back in the equation to find the value of x.

x + 3 + 1 = 12

Subtract 4 from both sides.

x = 8

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0