Galera preciso resolver essa questão é não sei como resolvê-la me ajudem por favor

Calculate f(3) by replacing X with 3:

f(x) = x^2 -1

f(3) = 3^2 -1

F(3) = 9-1

f(3) = 8

Now calculate f(-4) by replacing x with -4:

f(x) = x^2 -1

f(-4) = (-4)^2 - 1

f(-4) = 16 -1

f(-4) = 15

Now add f(3) to f(-4)

8 + 15 = 23

The answer is a) 23

answer: idk wbu

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)