How many kg of 30% salt solution by mass and 40% salt solution by mass should be mixed to form 200kg of 37% salt solution ?

Let us assume that x kg of 30% salt solution is mixed with (200-x) kg of 40% salt solution in order to obtain 200 kg of 37% salt solution.

We can set up a linear equation in terms of x by setting amount of total salt before mixing and after mixing equal to each other.

Therefore, 60 kg of 30% salt solution should be mixed with 140 kg of 40% solution.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this