Find the equation of a plane that is perpendicular to the vector −4i⃗ −4j⃗ −k⃗ and passing through the point (−2,−5,5)

hello

the equation of a plane that is ;  ax+by+cz +d =0

the vector perpendicular to this plane is : V(a,b,c)

in this exercice ; a = -4  b= -4  c = -1

then: the equation of a plane that is ;  -4x-4y-z +d =0

but the plane  passing through the point (−2,−5,5) :

-4(-2)-4(-5)-(5) +d =0

23+d =0

d =-23

the equation of a plane is : -4x-4y-z-23 =0

answer: its the third option.

step-by-step explanation:

i just took the test.

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