The price of a four-year dinner was $100 two decades ago. a report says that a dinner is 250% of what it was 20 years ago, how much would it cost today?

The original price of a shirt was $20. It was decreased to $15 . What is the percent decrease of the price of this shirt.

Solution to Problem 1:

The absolute decrease is

20 - 15 = $5

The percent decrease is the absolute decrease divided by the the original price (part/whole).

percent decease = 5 / 20 = 0.25

Multiply and divide 0.25 to obtain percent.

percent decease = 0.25 = 0.25 * 100 / 100 = 25 / 100 = 25%

Problem 2:

Mary has a monthly salary of $1200. She spends $280 per month on food. What percent of her monthly salary does she spend on food?

Solution to Problem 2:

The part of her salary that is spent on food is $280 out of her monthly salary of $1200

percent = part / whole = 280 / 1200 = 0.23 (rounded to 2 decimal places)

Multiply and divide 0.23 by 100 to convert in percent

percent = 0.23 * 100 / 100 = 23 / 100 = 23%

Problem 3:

The price of a pair of trousers was decreased by 22% to $30. What was the original price of the trousers?

Solution to Problem 3:

Let x be the original price and y be the absolute decrease. If the price was decreased to $30, then

x - y = 30

y is given by

y = 22% of x = (22 / 100) * x = 0.22 x

Substitute y by 0.22 x in the equation x - y = 30 and solve for x which the original price.

x - 0.22 x = 30

0.78 x = 30

x = $38.5

Check the solution to this problem by reducing the origonal price found $38.5 by 22% and see if it gives $30.

Problem 4:

The price of an item changed from $120 to $100. Then later the price decreased again from $100 to $80. Which of the two decreases was larger in percentage term?

Solution to Problem 4:

First decrease in percent

part / whole = (120 - 100) / 120 = 0.17 = 17%

Second decrease in percent

part / whole = (100 - 80) / 100 = 0.20 = 20%

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