Write the expression (4x-2)*6(2x-7) in the standard form of a quadratic expression ax^2 +bx+c. what are the values of the coefficients of each term and
the constant term. a=? b=? c=?

Ok so we just expand
using distributive propety
a(b+c)=ab+ac
we can put the 6 to the side since multiplication is commmutative and assocative
(4x-2)(6)(2x-7)=6[(4x-2)(2x-7)]
we distribute the inner for ease

(4x-2)(2x-7)=
(4x-2)(2x)+(4x-2)(-7)=
(4x)(2x)+(-2)(2x)+(4x)(-7)+(-2)(-7)=
8x^2+-4x+-28x+14=
8x^2-32x+14
then times 6 the whole thing for all terms
48x^2-192x+84
ax^2+bx+c

a=48
b=-192
c=84

So,

All we have to do is multiply out the terms.

(4x - 2)(6)(2x - 7)

Multiply the first and last terms (for no reason whatsoever).
(8x^2 - 32x + 14)(6)

Distribute the 6.
48x^2 - 192x + 84 (standard quadratic expression)

The standard form of a quadratic equation is:
ax^2 + bx + c

From this comparison, it is easy to see that a is 48, b is -192, and c is 84.  Notice that the negative/positive sign goes with each numerical coefficient.

So the values of the coefficients are 48, -192, and 84.

Gotta be d the music of previous eras