50 points lease find the area of an octagon with a radius of 6 meters. round your answer to the nearest tenth.

A regular octagon can be thought of as being composed of 4 "kite" shaped areas.

The area of a "kite" with diagonals d and w is

AreaKITE=d⋅w2.

(This is fairly easy to prove if it isn't a formula you already know).

Consider the "kite" PQCW in the diagram above.

∠QCW=π2 and |QC|=|WC|=r

s⇒|QW|=√2r (Pythagorean)

Therefore (since |PC|=r)

AreaPQCW=|PC|⋅|QW|2=r⋅√2r2=√2r^22

The octagon is composed of 4 such kites, so

AreaOctagon=2√2r^2

AreaOctogon=2√2(6)^2=101.823376491

AreaOctagon=101.8 units squared

here is the diagram https://d2gne97vdumgn3.cloudfront.net/api/file/80fl6nYTCaa5q8AZOyq0

angle addition postulate

2x=56

step-by-step explanation:

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)