Atube 1.20 m long is closed at one end. a stretched wire is placed near the open end. the wire is 0.330 m long and has a mass of 9.60 g. it is fixed at both ends and oscillates in its fundamental mode. by resonance, it sets the air column in the tube into oscillation at that column’s fundamental frequency. find (a) that frequency and (b) the tension in the wire.

Explanation:

tube:

f=v/4L = 343/(4*1.2)= 71.4583Hz tube's fundamental frequency  

wire:  

f=v/2L -> v=2Lf

v= 2*0.323*71.4583= 46.162m/s  

ρ= 0.0095/0.323= 0.02941kg/m  

v=√(T/ρ) -> T=v^2*ρ

T= 46.162^2*0.02941= 62.67[N] Tension of wire.

a 2,000 calorie based diet.

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.