I'm reasking a previous question to make it more clear. this is a linear equation that i must solve. it includes fractions (the 2 terms on the left side). here goes: x÷2 - (10x-25)÷10 = 3(x+3) - (x-14).

Assuming the equation is:

When fractions involve numeric denominators, the fractions can be removed by multiplying (both sides) by the LCM of the denominators.

Here the denominators are 2 and 10, hence the LCM is 10.

Multiply by 10 on both sides, not forgetting to distribute when multiplying on the right side:

simplify, remember that there are always implied parentheses around numerators and denominators:

Now, distribute, i.e. remove parentheses and distribute:

5x-10x+25=30x+90-10x+140

Simplify

-5x+25=20x+230

transpose terms

25-230=20x+5x

solve

x=-205/25=-41/5

In this particular case, we can also take advantage of the term

(10x-25)/10=5(2x-5)/10=(2x-5)/2 which greatly simplifies the solution process, because the LCM will then be 2 instead of 10.

If we do that, the solution will be:

Multiply by 2 on both sides, not forgetting to distribute when multiplying on the right side:

simplify, remember that there are always implied parentheses around numerators and denominators:

Now, distribute, i.e. remove parentheses and distribute:

Simplify

-x+5=4x+46

solve

5-46=4x+x

-41=5x

x=-41/5

with the same results.

the answer to this question is yes

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.