What is the probability that you would obtain a sum of 7 or a sum of 11 on the first roll? (rolling two dice.)

2/9

Step-by-step explanation:

Total outcome = 36

Sum of 7 = 6

Prob of sum of 7 = 6/36

Sum of 11 = 2

Prob of sum of 11 = 2/36

Prob of sum of 7 or 11 = 6/36+2/36

Prob of sum of 7 or 11 = (6+2)/36

Prob of sum of 7 or 11 = 8/36 = 2/9

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.