Triangle pqr is reflected across a line, p = (4,–5), and p’ = (–4, –5). what is the line of reflection? the x-axis the y-axis the line y = x the line y = –x

For this case we have that the original vertex is given by:

P = (4, -5)

We apply the following transformation:

(x, y) (-x, y)

We have then:

(4, -5) (- (4), -5) (- 4, -5)

Therefore, we have a reflection on the y axis.

The point obtained is the vertice:

P '= (-4, -5)

the line of reflection is:

the y-axis