Chemistry, 26.02.2020 13:07 emopandabogard4296

MnO2 + 4 HCI + Cl2 + MnCl2 + 2 H20

Given 145.7 grams of manganese (IV) oxide, how much hydrochloric acid (HCI) is
needed to use up the MnO2 completely?

Answers: 1

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MnO2 + 4 HCI + Cl2 + MnCl2 + 2 H20

Given 145.7 grams of manganese (IV) oxide, how much h...

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MnO2 + 4 HCI + Cl2 + MnCl2 + 2 H20 Given 145.7 grams of manganese (IV) oxide, how much hydrochloric acid (HCI) is needed to use up the MnO2 completely?

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Another question on Chemistry

MnO2 + 4 HCI + Cl2 + MnCl2 + 2 H20

Given 145.7 grams of manganese (IV) oxide, how much hydrochloric acid (HCI) is
needed to use up the MnO2 completely?