Find an equation of the tangent line to the curve at the given point. y = x3 − 2x + 1, (3, 22)

An equation of the tangent line to the curve at the given points is

Given the following data;

In this exercise, you're required to find an equation of the tangent line to the curve at the given points.

First of all, we would differentiate the value of y at point x = 3.

Substituting the value of x, we have;

y' = 25

Therefore, the slope (m) of the tangent line equation is 25.

Next, we would write an equation of the tangent line to the curve at the given points by using the formula;

Substituting the values into the formula, we have;

In conclusion, an equation of the tangent line to the curve at the given points is

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for finding the midpoint of any given 2 pair of points simply add the respective x coordinates with other x coordinate and the y coordinate with other y coordinate and divide them by 2

in your question it will be :

(3+1)/2 for the x coordinate of mid point i.e 2

[8+(-4)]/2 for the y coordinate of midpoint i.e 2

so coordinates of mid point of points (3,8) and (1,-4) will be (2,2)

what? ?

what type of question is thiss

step-by-step explanation: