The probability of drawing two red balls from a jar at random without replacement is 310 . the probability of drawing a red ball first is 916 . what is the probability of drawing a second red ball, given that the first ball drawn was red?

Drawing a first red ball: A
Drawing a second red ball: B

Probability of drawing two red balls: P(A ∩ B)=0.310
Probability of drawing a red ball first: P(A)=0.916
Probability of drawing a second red ball given that the first ball drawn was red: P(B\A)=?

P(B\A)=P(A ∩ B) P(A)→
P(B\A)=(0.310)(0.916)→
P(B\A)=0.28396→
P(B\A)=0.284

The probability of drawing a second red ball, given that the first ball drawn was red is 0.284

X^2 - 4x +(4/2^2) + y^2 + 8y + (8/2^2) = -4 + (4/2^2) + (8/2^2)(x + 2)^2 + (y + 4)^2 = -4 + 4 + 16your center is (-2, -4) and the radius is the sqrt of -4 + 4 + 16 which is 4