Klmn - parallelogram lf ⊥ kn , ld ⊥ nm m∠fld = 35° find: angles of klmn

Check the picture below.since the segment lf is perpendicular to kn and kn || lm, then lf is also perpendicular to lm, so the  ∡dlm is 90° - 35°, that makes  ∡lmd inside that triangle a 35° angle as you see in the picture.since  ∡m  =  ∡k = 35°, and  ∡m +  ∡n = 180°, then  ∡n = 180° - 35°, or 145°.and since  ∡n =  ∡l = 145°.