Evaluate the following in polar and standard forms. select all answers that apply. [3(cos(27°) isin(27°))]^5

Using De Moivre's formula

if z = a ( cos x + i sin x ) ⇒⇒⇒ ∴ z^n = a^n ( cos nx + i sin nx)

Part (1) 
∴ [ 3 (cos 27° + i sin 27°) ]⁵ = (3⁵) ( cos 5*27° + i sin 5*27°)
= 243 ( cos 135° + i sin 135°)  ⇒⇒⇒⇒ Polar form

Part (2)

The angle 135° in the second quadrant ⇒ sin is (+)  and cos is (-)
and its reference angle = 180° - 135° = 45°
sin 45° = cos 45°= 1/√2 = (√2)/2
∴ sin 135° = (√2)/2    and  cos 135° = -(√2)/2
∴ 243 ( cos 135° + i sin 135°) = 243 [ -(√2)/2 + i (√2)/2 ]

= - 243(√2)/2 + 243 (√2)/2 i ⇒⇒⇒⇒ standard form

The correct answers are options (1) and (3)

option (1) ⇒⇒⇒ 243 ( cos 135° + i sin 135°)  ⇒⇒⇒⇒ Polar form  
option (3) ⇒⇒⇒ - 243(√2)/2 + 243 (√2)/2 i     ⇒⇒⇒⇒ standard form

This polygon has 4 sides
180(4-2) = 180(2) = 360 degree
80+90+2x + 3x = 360
170+5x = 360
5x = 190
x= 38
measure of angle t is 2(38)= 76
the answer is c. trust me
hope this !