$7600 is invested for one year, part at 4% and the remainder at 5%. the income from the two investments is $338. find the amount invested at 4%.

its definatley   this on your answer choice?

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb