An equilibrium mixture of 3 kmol of CO, 2.5 kmol of O2, and 8 kmol of N2 is heated to 2600 K at a pressure of 5 atm. Determine the equilibrium composition of the mixture for these conditions.

Explanation:

Hello,

In this case, we consider the reaction:

For which the law of mass action is expressed as:

Whereas the exponents are referred to the stoichiometric coefficients in the chemical reaction. Moreover, in table A-28 (Cengel's thermodynamics) the natural logarithm of the undergoing reaction at 2600 K is 2.801, thus:

In such a way, in terms of the change the equilibrium goes:

Hence, solving for :

Thus, the moles at equilibrium:

Finally the compositions:

Best regards.

can you make it more obvious. i can't see it properly